Oi! This was done out of boredom. I've never seen anyone do this, and now I'm tired of waiting. So I think I figured out the Charlotte family. I suck at math, but I'm suprised that this shit works. Ok prepare to think. You might not understand a thing I'm saying but, just TRY: (keep in mind even though I barely use this) S=SONS H=HUSBANDS d=daughters #=Number Here's my prediction: ALL HUSBANDS, EXCEPT FOR 5, HAD A SON AND A DAUGHTER. What we know: There are 39 daughters, 46 sons, 43 husbands and one mother. The total is: 129 people My method for the SON part is trying to get the # of sons = to the # of husbands and see how many EXTRA sons there are. Here's what I'm doing: S: 46-3= 43 sons. Now that I made the # of sons equal to the # of husbands, I came to this conclusion: If there were never 3 extra sons and instead there were 43 sons, that means that every husband had 1 son, if they never had any daughters. BUT there are 2 possibilities: 1 H could've had 4 S or 3 H had 2 Sons each We'll see which one works later. I'll put everything together at the end. My method for the DAUGHTER part is a bit more different and complex. Here's what I am doing: 39 Daughters right? 43 HUSBANDS - 4 = 39 If there were never 4 extra husbands then each H would have 1 DAUGHTER, if they never had sons. BUT there's a problem: LOLA and that lady in Ch 825 are probably twins. So 1 husband had more than 1 daughter so there has to be 38 husbands in order for that to work. SO THERE ARE ACTUALLY 5 EXTRA HUSBANDS. So 38 husbands had 39 daughters. Wait, but how is it possible for the # of Daughters to be more than # of husbands? Well like I said, there is ONE set of twins. ONLY ONE. Why?! because if they never had twins then subtract 2 from the # of daughters. That also means that there would be 1 husband out. Here's what I mean: 39 daughters - 2 daughters(twins) = 37 daughters Only 1 husband could have had 2 twins so: 38 husbands - 1 husband = 37 husbands 37 = 37. The #'s match. But what about the rest of the Husbands. 43 - 38 = 5 husbands. So there are 5 husbands left which I mentioned before. OK LET'S PUT IT TOGETHER AND SEE: I'm going to use the lowest # of siblings. The Daughters. I will try and make the sons equal to 39. For husbands, they will equal to 38. and whatever I subtracted to do that, will be the # of husbands left. Same for the sons. 43-5=38 husbands. 5 Husbands left 46-7=39 sons. 7 sons left. 5 husbands left. Remember the possiblities in the Son part? Well, the only onne that works is that 3 husbands had 2 sons each. The reason is because we need to get to 43 husbands and 46 sons in order for this to work. So if there are 3 more husbands, then: 38+3=41 Now there are 2 more husbands left. One husband is the husband that gave birth to the twins of the daughters. The LAST husband I'm getting to. In total: 41+2=43 husbands. WE DID THE HUSBAND PART! 3 husbands each had 2 sons, 1 husband had twins(2 daughter), and 1 husband is left. Now for the SONS: If 3 H had 2 sons each, then that means 6 sons were born. Remember when we did this: 46 sons - 7=39 sons. That means there is 1 son missing. THIS SON WILL BE PUT WITH THE LAST HUSBAND I MENTIONED. SO: 7 extra sons + 39 sons = 46 sons in all Now, this part I didn't plan out but, using the numbers I have, every son had to have a sister EXCEPT for 7 sons. That means that, every husband had a son and a daughter, EXCEPT for 5. Those 5 husbands. 3 H each had 2 sons each, 1 had twin daughters, and the last one had only 1 son. So now that that's done, my experiment is complete. Wait! but who's the middle child?? Well, the total siblings is 85. Since this # is odd then there has to be a # in the middle. So what I did was find the middle child by doing this: 46 - 39 = 7. There are seven numbers between 46 and 39. They are 1=45 2=44 3=43 4=42 5=41 6=40 7=39 THE 42ND SIBLING IS THE MIDDLE CHILD. Its hard to decide if it is a daughter or a son. But I did this: SON - DAUGHTER = SAME DIFFERENCE 45-38=7 44-37=7 43-36=7 42-35=7 40-33=7 41-34=7 39-32=7 Note: There's actually a possibility that this 42nd son can be the son that doesn't have any brothers or sisters and his dad is the husband that has only 1 son. That would mean that the 35th daughter doesn't have a dad. It could be that the 42nd son or the 35th daughter is the middle child but it depends on when they were born. I think the son would be born first.............. Speculation: HOLD ON. WAIT!@ OH SH!T! ISN'T PUDDING THE 35TH DAUGHTER. WELL FUCK, PUDDING MIGHT BE THE MIDDLE CHILD THEN. AND THE MIDDLE CHILD IS ALWAYS THE FUCKING ONE IN THE MIDDLE OF EVERYTHING. I KNOW HOW IT FEELS, I'M THE MIDDLE CHILD TOO. I KNEW THERE WAS SOMETHING SPECIAL ABOUT PUDDING. ALSO THERE'S A POSSIBILITY THAT PUDDING HAS A BROTHER. But, since ONE of the husbands, HAVE to have only 1 child, which is a son...........PUDDING MIGHT BE ADOPTED!!!!!!! Anyways, I hope your brain is okay. I did this out of boredom and I suck at math, but it fucking worked. I hope you understand everything. I got math finals this week too but Thank you for reading if you did.